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Integ Trans Syste 27634 pair #381739513
details
property
value
status
complete
benchmark
afagx1.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n093.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.555022001266 seconds
cpu usage
0.578836012
max memory
1.1255808E7
stage attributes
key
value
output-size
2063
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f9#(x1, x2) -> f8#(x1, x2) f8#(I0, I1) -> f2#(I0, 1) f5#(I4, I5) -> f4#(I4, I5) f4#(I6, I7) -> f5#(I6, I7) f2#(I8, I9) -> f3#(rnd1, I9) [rnd1 = rnd1] f3#(I10, I11) -> f1#(I10, I11) [1 + I10 <= 0] f3#(I12, I13) -> f1#(I12, I13) [1 <= I12] f3#(I14, I15) -> f4#(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0] f1#(I16, I17) -> f2#(I16, I17) R = f9(x1, x2) -> f8(x1, x2) f8(I0, I1) -> f2(I0, 1) f6(I2, I3) -> f7(I2, I3) f5(I4, I5) -> f4(I4, I5) f4(I6, I7) -> f5(I6, I7) f2(I8, I9) -> f3(rnd1, I9) [rnd1 = rnd1] f3(I10, I11) -> f1(I10, I11) [1 + I10 <= 0] f3(I12, I13) -> f1(I12, I13) [1 <= I12] f3(I14, I15) -> f4(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0] f1(I16, I17) -> f2(I16, I17) The dependency graph for this problem is: 0 -> 1 1 -> 4 2 -> 3 3 -> 2 4 -> 5, 6, 7 5 -> 8 6 -> 8 7 -> 3 8 -> 4 Where: 0) f9#(x1, x2) -> f8#(x1, x2) 1) f8#(I0, I1) -> f2#(I0, 1) 2) f5#(I4, I5) -> f4#(I4, I5) 3) f4#(I6, I7) -> f5#(I6, I7) 4) f2#(I8, I9) -> f3#(rnd1, I9) [rnd1 = rnd1] 5) f3#(I10, I11) -> f1#(I10, I11) [1 + I10 <= 0] 6) f3#(I12, I13) -> f1#(I12, I13) [1 <= I12] 7) f3#(I14, I15) -> f4#(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0] 8) f1#(I16, I17) -> f2#(I16, I17) We have the following SCCs. { 4, 5, 6, 8 } { 2, 3 } DP problem for innermost termination. P = f5#(I4, I5) -> f4#(I4, I5) f4#(I6, I7) -> f5#(I6, I7) R = f9(x1, x2) -> f8(x1, x2) f8(I0, I1) -> f2(I0, 1) f6(I2, I3) -> f7(I2, I3) f5(I4, I5) -> f4(I4, I5) f4(I6, I7) -> f5(I6, I7) f2(I8, I9) -> f3(rnd1, I9) [rnd1 = rnd1] f3(I10, I11) -> f1(I10, I11) [1 + I10 <= 0] f3(I12, I13) -> f1(I12, I13) [1 <= I12] f3(I14, I15) -> f4(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0] f1(I16, I17) -> f2(I16, I17)
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