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Integ Trans Syste 27634 pair #381740008
details
property
value
status
complete
benchmark
fun4.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n002.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
10.6590850353 seconds
cpu usage
11.287767998
max memory
2.6984448E7
stage attributes
key
value
output-size
3287
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) f4#(I0, I1, I2, I3, I4) -> f3#(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4] f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9] f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12] f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19] f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25] R = f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) f4(I0, I1, I2, I3, I4) -> f3(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4] f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9] f3(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12] f3(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19] f2(I20, I21, I22, I23, I24) -> f3(I20, I21, I23, I23, I24) f1(I25, I26, I27, I28, I29) -> f2(I25, I26, I27, I28, I29) [I25 = I25] The dependency graph for this problem is: 0 -> 1 1 -> 2, 3, 4 2 -> 6 3 -> 6 4 -> 6 5 -> 2, 3, 4 6 -> 5 Where: 0) f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) 1) f4#(I0, I1, I2, I3, I4) -> f3#(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4] 2) f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9] 3) f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12] 4) f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19] 5) f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) 6) f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25] We have the following SCCs. { 2, 3, 4, 5, 6 } DP problem for innermost termination. P = f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9] f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12] f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19] f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25] R = f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) f4(I0, I1, I2, I3, I4) -> f3(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4] f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9] f3(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12] f3(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19] f2(I20, I21, I22, I23, I24) -> f3(I20, I21, I23, I23, I24) f1(I25, I26, I27, I28, I29) -> f2(I25, I26, I27, I28, I29) [I25 = I25]
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