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Integ Trans Syste 27634 pair #381740029
details
property
value
status
complete
benchmark
d.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n023.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
3.8880879879 seconds
cpu usage
4.141337255
max memory
2.4383488E7
stage attributes
key
value
output-size
1879
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f4#(x1, x2, x3, x4) -> f3#(x1, x2, x3, x4) f3#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0] R = f4(x1, x2, x3, x4) -> f3(x1, x2, x3, x4) f3(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) f2(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) f1(I8, I9, I10, I11) -> f2(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1, x2, x3, x4) -> f3#(x1, x2, x3, x4) 1) f3#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) 2) f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 3) f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0] R = f4(x1, x2, x3, x4) -> f3(x1, x2, x3, x4) f3(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) f2(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) f1(I8, I9, I10, I11) -> f2(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]
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