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Compl Integ Trans Syste 26843 pair #381744248
details
property
value
status
complete
benchmark
direct_n_log_n.koat
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n111.star.cs.uiowa.edu
space
misc
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
2.19369292259 seconds
cpu usage
4.400364759
max memory
2.42143232E8
stage attributes
key
value
output-size
2822
starexec-result
WORST_CASE(?, O(n^1))
output
/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(?, O(n^1)) proof of /export/starexec/sandbox/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, max(3, 3 + 4 * Arg_0) + nat(8 * Arg_0)). (0) CpxIntTrs (1) Koat2 Proof [FINISHED, 154 ms] (2) BOUNDS(1, max(3, 3 + 4 * Arg_0) + nat(8 * Arg_0)) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: start(A) -> Com_1(a(A)) :|: A >= 1 start(A) -> Com_1(a(A)) :|: A >= 2 start(A) -> Com_1(a(A)) :|: A >= 4 a(A) -> Com_1(a(B)) :|: 2 * B >= 2 && A >= 2 * B && A <= 2 * B a(A) -> Com_1(a(B)) :|: 2 * B >= 1 && A >= 2 * B + 1 && A <= 2 * B + 1 The start-symbols are:[start_1] ---------------------------------------- (1) Koat2 Proof (FINISHED) YES( ?, 3+2*(2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])) {O(n)}) Initial Complexity Problem: Start: start Program_Vars: Arg_0 Temp_Vars: B Locations: a, start Transitions: a(Arg_0) -> a(B):|:2 <= (2)*B && Arg_0 <= (2)*B && (2)*B <= Arg_0 a(Arg_0) -> a(B):|:1 <= (2)*B && Arg_0 <= (2)*B+1 && (2)*B+1 <= Arg_0 start(Arg_0) -> a(Arg_0):|:1 <= Arg_0 start(Arg_0) -> a(Arg_0):|:2 <= Arg_0 start(Arg_0) -> a(Arg_0):|:4 <= Arg_0 Timebounds: Overall timebound: 3+2*(2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])) {O(n)} 3: a->a: 2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0]) {O(n)} 4: a->a: 2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0]) {O(n)} 0: start->a: 1 {O(1)} 1: start->a: 1 {O(1)} 2: start->a: 1 {O(1)} Costbounds: Overall costbound: 3+2*(2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])) {O(n)} 3: a->a: 2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0]) {O(n)} 4: a->a: 2*max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0])+max([0, Arg_0]) {O(n)} 0: start->a: 1 {O(1)} 1: start->a: 1 {O(1)} 2: start->a: 1 {O(1)} Sizebounds: `Lower: 3: a->a, Arg_0: 1 {O(1)}
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