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SRS_Standard 2019-03-29 03.29 pair #432289422
details
property
value
status
complete
benchmark
09.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n013.star.cs.uiowa.edu
space
Bouchare_06
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
0.631823 seconds
cpu usage
0.909234
user time
0.629077
system time
0.280157
max virtual memory
2310068.0
max residence set size
59224.0
stage attributes
key
value
starexec-result
NO
output
0.58/0.62 NO 0.58/0.62 0.58/0.62 Problem: 0.58/0.62 b(a(a(x1))) -> a(x1) 0.58/0.62 a(a(a(x1))) -> b(b(b(x1))) 0.58/0.62 b(b(x1)) -> a(b(a(x1))) 0.58/0.62 0.58/0.62 Proof: 0.58/0.62 String Reversal Processor: 0.58/0.62 a(a(b(x1))) -> a(x1) 0.58/0.62 a(a(a(x1))) -> b(b(b(x1))) 0.58/0.62 b(b(x1)) -> a(b(a(x1))) 0.58/0.62 Unfolding Processor: 0.58/0.62 loop length: 6 0.58/0.62 terms: 0.58/0.62 a(a(a(b(a(a(x2342)))))) 0.58/0.62 b(b(b(b(a(a(x2342)))))) 0.58/0.62 a(b(a(b(b(a(a(x2342))))))) 0.58/0.62 a(b(a(a(b(a(a(a(x2342)))))))) 0.58/0.62 a(b(a(a(b(b(b(b(x2342)))))))) 0.58/0.62 a(b(a(a(a(b(a(b(b(x2342))))))))) 0.58/0.62 context: a(b([])) 0.58/0.62 substitution: 0.58/0.62 x2342 -> b(a(x2342)) 0.58/0.62 Qed 0.58/0.63 EOF
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