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SRS_Standard 2019-03-29 03.29 pair #432294498
details
property
value
status
complete
benchmark
random-470.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
5.51977 seconds
cpu usage
20.3848
user time
18.423
system time
1.9618
max virtual memory
3598160.0
max residence set size
83784.0
stage attributes
key
value
starexec-result
YES
output
19.77/5.50 YES 19.77/5.51 19.77/5.51 Problem: 19.77/5.51 a(b(a(a(x1)))) -> a(b(b(a(x1)))) 19.77/5.51 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 19.77/5.51 b(b(a(a(x1)))) -> a(b(a(a(x1)))) 19.77/5.51 b(b(b(b(x1)))) -> a(a(a(a(x1)))) 19.77/5.51 19.77/5.51 Proof: 19.77/5.51 Matrix Interpretation Processor: dim=3 19.77/5.51 19.77/5.51 interpretation: 19.77/5.51 [1 1 0] [0] 19.77/5.51 [b](x0) = [0 0 1]x0 + [0] 19.77/5.51 [1 0 0] [1], 19.77/5.51 19.77/5.51 [1 0 0] 19.77/5.51 [a](x0) = [0 0 0]x0 19.77/5.51 [0 0 0] 19.77/5.51 orientation: 19.77/5.51 [1 0 0] [1 0 0] 19.77/5.51 a(b(a(a(x1)))) = [0 0 0]x1 >= [0 0 0]x1 = a(b(b(a(x1)))) 19.77/5.51 [0 0 0] [0 0 0] 19.77/5.51 19.77/5.51 [1 1 0] [1 0 0] 19.77/5.51 a(b(a(b(x1)))) = [0 0 0]x1 >= [0 0 0]x1 = a(b(b(a(x1)))) 19.77/5.51 [0 0 0] [0 0 0] 19.77/5.51 19.77/5.51 [1 0 0] [0] [1 0 0] 19.77/5.51 b(b(a(a(x1)))) = [1 0 0]x1 + [1] >= [0 0 0]x1 = a(b(a(a(x1)))) 19.77/5.51 [1 0 0] [1] [0 0 0] 19.77/5.51 19.77/5.51 [3 2 1] [2] [1 0 0] 19.77/5.51 b(b(b(b(x1)))) = [1 1 1]x1 + [1] >= [0 0 0]x1 = a(a(a(a(x1)))) 19.77/5.51 [2 1 1] [2] [0 0 0] 19.77/5.51 problem: 19.77/5.51 a(b(a(a(x1)))) -> a(b(b(a(x1)))) 19.77/5.51 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 19.77/5.51 b(b(a(a(x1)))) -> a(b(a(a(x1)))) 19.77/5.51 Matrix Interpretation Processor: dim=3 19.77/5.51 19.77/5.51 interpretation: 19.77/5.51 [1 0 1] [1] 19.77/5.51 [b](x0) = [0 0 2]x0 + [0] 19.77/5.51 [0 2 0] [0], 19.77/5.51 19.77/5.51 [1 0 0] [1] 19.77/5.51 [a](x0) = [0 0 0]x0 + [0] 19.77/5.51 [1 0 0] [0] 19.77/5.51 orientation: 19.77/5.51 [2 0 0] [5] [2 0 0] [4] 19.77/5.51 a(b(a(a(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(b(a(x1)))) 19.77/5.51 [2 0 0] [4] [2 0 0] [3] 19.77/5.51 19.77/5.51 [2 0 2] [5] [2 0 0] [4] 19.77/5.51 a(b(a(b(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(b(a(x1)))) 19.77/5.51 [2 0 2] [4] [2 0 0] [3] 19.77/5.51 19.77/5.51 [2 0 0] [5] [2 0 0] [5] 19.77/5.51 b(b(a(a(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(a(a(x1)))) 19.77/5.51 [4 0 0] [4] [2 0 0] [4] 19.77/5.51 problem: 19.77/5.51 b(b(a(a(x1)))) -> a(b(a(a(x1)))) 19.77/5.51 String Reversal Processor: 19.77/5.51 a(a(b(b(x1)))) -> a(a(b(a(x1)))) 19.77/5.51 KBO Processor: 19.77/5.51 weight function: 19.77/5.51 w0 = 1 19.77/5.51 w(b) = w(a) = 1 19.77/5.51 precedence: 19.77/5.51 b > a 19.77/5.51 problem: 19.77/5.51 19.77/5.51 Qed 20.36/5.51 EOF
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