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TRS Standard pair #487067657
details
property
value
status
complete
benchmark
4.56.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n189.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.359025 seconds
cpu usage
0.43341
user time
0.334734
system time
0.098676
max virtual memory
96176.0
max residence set size
56152.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: f(a(),b()) -> f(a(),c()) f(c(),d()) -> f(b(),d()) Proof: Extended Uncurrying Processor: application symbol: f symbol table: d ==> d0/0 c ==> c0/0 c1/1 b ==> b0/0 b1/1 a ==> a0/0 a1/1 uncurry-rules: f(a0(),x0) -> a1(x0) f(b0(),x2) -> b1(x2) f(c0(),x4) -> c1(x4) eta-rules: problem: a1(b0()) -> a1(c0()) c1(d0()) -> b1(d0()) f(a0(),x0) -> a1(x0) f(b0(),x2) -> b1(x2) f(c0(),x4) -> c1(x4) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [b1](x0) = [0 0 1]x0 [0 0 0] , [0] [a0] = [0] [0], [1 1 1] [c1](x0) = [0 0 1]x0 [1 0 0] , [0] [b0] = [1] [0], [0] [d0] = [0] [1], [0] [c0] = [0] [0], [1 1 0] [a1](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [1 1 1] [1] [f](x0, x1) = [0 0 0]x0 + [0 0 1]x1 + [0] [0 0 0] [1 0 0] [0] orientation: [1] [0] a1(b0()) = [0] >= [0] = a1(c0()) [0] [0] [1] [0] c1(d0()) = [1] >= [1] = b1(d0()) [0] [0] [1 1 1] [1] [1 1 0] f(a0(),x0) = [0 0 1]x0 + [0] >= [0 0 0]x0 = a1(x0) [1 0 0] [0] [0 0 0] [1 1 1] [1] [1 0 0] f(b0(),x2) = [0 0 1]x2 + [0] >= [0 0 1]x2 = b1(x2) [1 0 0] [0] [0 0 0] [1 1 1] [1] [1 1 1] f(c0(),x4) = [0 0 1]x4 + [0] >= [0 0 1]x4 = c1(x4) [1 0 0] [0] [1 0 0] problem: Qed
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