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TRS Standard pair #487071545
details
property
value
status
complete
benchmark
Ex14_Luc06_FR.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n173.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
NTI-TC20-firstrun
configuration
Default 200
runtime (wallclock)
0.179578 seconds
cpu usage
0.243012
user time
0.190441
system time
0.052571
max virtual memory
113188.0
max residence set size
54156.0
stage attributes
key
value
starexec-result
NO
output
NO Prover = TRS(tech=GUIDED_UNF, nb_unfoldings=unlimited, unfold_variables=true, strategy=LEFTMOST_NE) ** BEGIN proof argument ** The following rule was generated while unfolding the analyzed TRS: [iteration = 5] f(b,b) -> f(b,b) Let l be the left-hand side and r be the right-hand side of this rule. Let p = epsilon, theta1 = {} and theta2 = {}. We have r|p = f(b,b) and theta2(theta1(l)) = theta1(r|p). Hence, the term theta1(l) = f(b,b) loops w.r.t. the analyzed TRS. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Searching for a loop by unfolding (unfolding of variable subterms: ON)... # Iteration 0: no loop detected, 1 unfolded rule generated. # Iteration 1: no loop detected, 1 unfolded rule generated. # Iteration 2: no loop detected, 1 unfolded rule generated. # Iteration 3: no loop detected, 1 unfolded rule generated. # Iteration 4: no loop detected, 4 unfolded rules generated. # Iteration 5: loop detected, 1 unfolded rule generated. Here is the successful unfolding. Let IR be the TRS under analysis. L0 = [f^#(_0,_0) -> h^#(a), h^#(_1) -> g^#(_1,_1), g^#(a,_2) -> f^#(b,activate(_2))] is in U_IR^0. We merge the first and the second rule of L0. ==> L1 = [f^#(_0,_0) -> g^#(a,a), g^#(a,_1) -> f^#(b,activate(_1))] is in U_IR^1. We merge the first and the second rule of L1. ==> L2 = f^#(_0,_0) -> f^#(b,activate(a)) is in U_IR^2. Let p2 = [0]. The subterm at position p2 in the left-hand side of the rule of L2 unifies with the subterm at position p2 in the right-hand side of the rule of L2. ==> L3 = f^#(b,b) -> f^#(b,activate(a)) is in U_IR^3. Let p3 = [1]. We unfold the rule of L3 forwards at position p3 with the rule activate(_0) -> _0. ==> L4 = f^#(b,b) -> f^#(b,a) is in U_IR^4. Let p4 = [1]. We unfold the rule of L4 forwards at position p4 with the rule a -> b. ==> L5 = f^#(b,b) -> f^#(b,b) is in U_IR^5. ** END proof description ** Proof stopped at iteration 5 Number of unfolded rules generated by this proof = 9 Number of unfolded rules generated by all the parallel proofs = 9
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