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SRS Standard pair #487089892
details
property
value
status
complete
benchmark
abaabababa-aababababaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n145.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.69732 seconds
cpu usage
4.00352
user time
3.82587
system time
0.17765
max virtual memory
1.9606264E7
max residence set size
331096.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(b(a(x1)))))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 582, 583, 584, 585, 586, 587, 588, 589, 590, 591, 592, 593, 594, 595, 596, 597, 598, 599, 600, 601, 602, 603 Node 582 is start node and node 583 is final node. Those nodes are connected through the following edges: * 582 to 584 labelled b_1(0)* 583 to 583 labelled #_1(0)* 584 to 585 labelled a_1(0)* 585 to 586 labelled a_1(0)* 586 to 587 labelled b_1(0)* 587 to 588 labelled a_1(0)* 587 to 594 labelled b_1(1)* 588 to 589 labelled b_1(0)* 589 to 590 labelled a_1(0)* 589 to 594 labelled b_1(1)* 590 to 591 labelled b_1(0)* 591 to 592 labelled a_1(0)* 591 to 594 labelled b_1(1)* 592 to 593 labelled b_1(0)* 593 to 583 labelled a_1(0)* 593 to 594 labelled b_1(1)* 594 to 595 labelled a_1(1)* 595 to 596 labelled a_1(1)* 596 to 597 labelled b_1(1)* 597 to 598 labelled a_1(1)* 597 to 594 labelled b_1(1)* 598 to 599 labelled b_1(1)* 599 to 600 labelled a_1(1)* 599 to 594 labelled b_1(1)* 600 to 601 labelled b_1(1)* 601 to 602 labelled a_1(1)* 601 to 594 labelled b_1(1)* 602 to 603 labelled b_1(1)* 603 to 583 labelled a_1(1)* 603 to 594 labelled b_1(1) ---------------------------------------- (6) YES
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