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SRS Standard pair #487090144
details
property
value
status
complete
benchmark
abbcaaaaa-aaaaaabbcaabbc.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n138.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.71013 seconds
cpu usage
4.08318
user time
3.90814
system time
0.175034
max virtual memory
1.9143968E7
max residence set size
324684.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(c(a(a(a(a(a(x1))))))))) -> a(a(a(a(a(a(b(b(c(a(a(b(b(c(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(b(b(a(x1))))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(c(b(b(a(x1))))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 487, 488, 489, 490, 491, 492, 493, 494, 495, 496, 497, 498, 499, 500, 501, 502, 503, 504, 505, 506, 507, 508, 509, 510, 511, 512 Node 487 is start node and node 488 is final node. Those nodes are connected through the following edges: * 487 to 489 labelled c_1(0)* 488 to 488 labelled #_1(0)* 489 to 490 labelled b_1(0)* 490 to 491 labelled b_1(0)* 491 to 492 labelled a_1(0)* 492 to 493 labelled a_1(0)* 493 to 494 labelled c_1(0)* 494 to 495 labelled b_1(0)* 495 to 496 labelled b_1(0)* 496 to 497 labelled a_1(0)* 496 to 501 labelled c_1(1)* 497 to 498 labelled a_1(0)* 497 to 501 labelled c_1(1)* 498 to 499 labelled a_1(0)* 498 to 501 labelled c_1(1)* 499 to 500 labelled a_1(0)* 499 to 501 labelled c_1(1)* 500 to 488 labelled a_1(0)* 500 to 501 labelled c_1(1)* 501 to 502 labelled b_1(1)* 502 to 503 labelled b_1(1)* 503 to 504 labelled a_1(1)* 504 to 505 labelled a_1(1)* 505 to 506 labelled c_1(1)* 506 to 507 labelled b_1(1)* 507 to 508 labelled b_1(1)* 508 to 509 labelled a_1(1)* 508 to 501 labelled c_1(1)* 509 to 510 labelled a_1(1)* 509 to 501 labelled c_1(1)* 510 to 511 labelled a_1(1)* 510 to 501 labelled c_1(1)* 511 to 512 labelled a_1(1)* 511 to 501 labelled c_1(1)* 512 to 488 labelled a_1(1)* 512 to 501 labelled c_1(1) ---------------------------------------- (6) YES
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