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SRS Standard pair #487090618
details
property
value
status
complete
benchmark
abaaaaaa-aaaaaaabaaabab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n148.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.58828 seconds
cpu usage
3.51994
user time
3.36421
system time
0.155734
max virtual memory
1.9076148E7
max residence set size
257208.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(a(x1)))))))) -> a(a(a(a(a(a(a(b(a(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 159, 160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170 Node 84 is start node and node 85 is final node. Those nodes are connected through the following edges: * 84 to 86 labelled b_1(0)* 85 to 85 labelled #_1(0)* 86 to 87 labelled a_1(0)* 87 to 88 labelled b_1(0)* 88 to 89 labelled a_1(0)* 89 to 90 labelled a_1(0)* 90 to 91 labelled a_1(0)* 91 to 92 labelled b_1(0)* 92 to 93 labelled a_1(0)* 92 to 159 labelled b_1(1)* 93 to 94 labelled a_1(0)* 93 to 159 labelled b_1(1)* 94 to 95 labelled a_1(0)* 94 to 159 labelled b_1(1)* 95 to 96 labelled a_1(0)* 95 to 159 labelled b_1(1)* 96 to 97 labelled a_1(0)* 96 to 159 labelled b_1(1)* 97 to 85 labelled a_1(0)* 97 to 159 labelled b_1(1)* 159 to 160 labelled a_1(1)* 160 to 161 labelled b_1(1)* 161 to 162 labelled a_1(1)* 162 to 163 labelled a_1(1)* 163 to 164 labelled a_1(1)* 164 to 165 labelled b_1(1)* 165 to 166 labelled a_1(1)* 165 to 159 labelled b_1(1)* 166 to 167 labelled a_1(1)* 166 to 159 labelled b_1(1)* 167 to 168 labelled a_1(1)* 167 to 159 labelled b_1(1)* 168 to 169 labelled a_1(1)* 168 to 159 labelled b_1(1)* 169 to 170 labelled a_1(1)* 169 to 159 labelled b_1(1)* 170 to 85 labelled a_1(1)* 170 to 159 labelled b_1(1) ---------------------------------------- (6) YES
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