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SRS Standard pair #487091969
details
property
value
status
complete
benchmark
dup11.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n145.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
MultumNonMulta 20 June 2020 20G sparse
configuration
default
runtime (wallclock)
0.63556 seconds
cpu usage
1.38531
user time
1.21465
system time
0.170663
max virtual memory
2.565008E7
max residence set size
210448.0
stage attributes
key
value
starexec-result
YES
output
YES After renaming modulo { a->0, b->1, C->2, c->3, A->4, B->5 }, it remains to prove termination of the 24-rule system { 0 0 1 1 -> 2 2 , 1 1 3 3 -> 4 4 , 3 3 0 0 -> 5 5 , 4 4 2 2 -> 1 1 , 2 2 5 5 -> 0 0 , 5 5 4 4 -> 3 3 , 0 0 0 0 0 0 0 0 0 0 -> 4 4 4 4 4 4 , 4 4 4 4 4 4 4 4 -> 0 0 0 0 0 0 0 0 , 1 1 1 1 1 1 1 1 1 1 -> 5 5 5 5 5 5 , 5 5 5 5 5 5 5 5 -> 1 1 1 1 1 1 1 1 , 3 3 3 3 3 3 3 3 3 3 -> 2 2 2 2 2 2 , 2 2 2 2 2 2 2 2 -> 3 3 3 3 3 3 3 3 , 5 5 0 0 0 0 0 0 0 0 -> 3 3 4 4 4 4 4 4 , 4 4 4 4 4 4 1 1 -> 0 0 0 0 0 0 0 0 2 2 , 2 2 1 1 1 1 1 1 1 1 -> 0 0 5 5 5 5 5 5 , 5 5 5 5 5 5 3 3 -> 1 1 1 1 1 1 1 1 4 4 , 4 4 3 3 3 3 3 3 3 3 -> 1 1 2 2 2 2 2 2 , 2 2 2 2 2 2 0 0 -> 3 3 3 3 3 3 3 3 5 5 , 0 0 4 4 -> , 4 4 0 0 -> , 1 1 5 5 -> , 5 5 1 1 -> , 3 3 2 2 -> , 2 2 3 3 -> } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 2 | | 0 1 | \ / 1 is interpreted by / \ | 1 2 | | 0 1 | \ / 2 is interpreted by / \ | 1 3 | | 0 1 | \ / 3 is interpreted by / \ | 1 2 | | 0 1 | \ / 4 is interpreted by / \ | 1 3 | | 0 1 | \ / 5 is interpreted by / \ | 1 3 | | 0 1 | \ / After renaming modulo { 5->0, 0->1, 3->2, 4->3, 1->4, 2->5 }, it remains to prove termination of the 6-rule system { 0 0 1 1 1 1 1 1 1 1 -> 2 2 3 3 3 3 3 3 , 3 3 3 3 3 3 4 4 -> 1 1 1 1 1 1 1 1 5 5 , 5 5 4 4 4 4 4 4 4 4 -> 1 1 0 0 0 0 0 0 , 0 0 0 0 0 0 2 2 -> 4 4 4 4 4 4 4 4 3 3 , 3 3 2 2 2 2 2 2 2 2 -> 4 4 5 5 5 5 5 5 , 5 5 5 5 5 5 1 1 -> 2 2 2 2 2 2 2 2 0 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (0,false)->1, (1,false)->2, (3,true)->3, (3,false)->4, (4,false)->5, (5,true)->6, (5,false)->7, (2,false)->8 }, it remains to prove termination of the 30-rule system { 0 1 2 2 2 2 2 2 2 2 -> 3 4 4 4 4 4 , 0 1 2 2 2 2 2 2 2 2 -> 3 4 4 4 4 , 0 1 2 2 2 2 2 2 2 2 -> 3 4 4 4 , 0 1 2 2 2 2 2 2 2 2 -> 3 4 4 , 0 1 2 2 2 2 2 2 2 2 -> 3 4 , 0 1 2 2 2 2 2 2 2 2 -> 3 , 3 4 4 4 4 4 5 5 -> 6 7 , 3 4 4 4 4 4 5 5 -> 6 , 6 7 5 5 5 5 5 5 5 5 -> 0 1 1 1 1 1 , 6 7 5 5 5 5 5 5 5 5 -> 0 1 1 1 1 , 6 7 5 5 5 5 5 5 5 5 -> 0 1 1 1 , 6 7 5 5 5 5 5 5 5 5 -> 0 1 1 , 6 7 5 5 5 5 5 5 5 5 -> 0 1 , 6 7 5 5 5 5 5 5 5 5 -> 0 , 0 1 1 1 1 1 8 8 -> 3 4 , 0 1 1 1 1 1 8 8 -> 3 , 3 4 8 8 8 8 8 8 8 8 -> 6 7 7 7 7 7 , 3 4 8 8 8 8 8 8 8 8 -> 6 7 7 7 7 , 3 4 8 8 8 8 8 8 8 8 -> 6 7 7 7 , 3 4 8 8 8 8 8 8 8 8 -> 6 7 7 , 3 4 8 8 8 8 8 8 8 8 -> 6 7 , 3 4 8 8 8 8 8 8 8 8 -> 6 ,
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