details

property	value
status	complete
benchmark	#4.22.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n143.star.cs.uiowa.edu
space	Strategy_removed_AG01

run statistics

property	value
solver	AProVE
configuration	complexity
runtime (wallclock)	4.14332 seconds
cpu usage	12.7236
user time	11.7427
system time	0.980912
max virtual memory	1.8611908E7
max residence set size	3551720.0

stage attributes

key	value
starexec-result	WORST_CASE(Omega(n^1), O(n^1))

output

WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). (0) CpxTRS (1) CpxTrsToCdtProof [UPPER BOUND(ID), 10 ms] (2) CdtProblem (3) CdtLeafRemovalProof [BOTH BOUNDS(ID, ID), 0 ms] (4) CdtProblem (5) CdtUsableRulesProof [BOTH BOUNDS(ID, ID), 0 ms] (6) CdtProblem (7) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 27 ms] (8) CdtProblem (9) CdtKnowledgeProof [FINISHED, 0 ms] (10) BOUNDS(1, 1) (11) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (12) TRS for Loop Detection (13) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] (14) BEST (15) proven lower bound (16) LowerBoundPropagationProof [FINISHED, 0 ms] (17) BOUNDS(n^1, INF) (18) TRS for Loop Detection ---------------------------------------- (0) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: quot(0, s(y), s(z)) -> 0 quot(s(x), s(y), z) -> quot(x, y, z) quot(x, 0, s(z)) -> s(quot(x, s(z), s(z))) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (1) CpxTrsToCdtProof (UPPER BOUND(ID)) Converted Cpx (relative) TRS to CDT ---------------------------------------- (2) Obligation: Complexity Dependency Tuples Problem Rules: quot(0, s(z0), s(z1)) -> 0 quot(s(z0), s(z1), z2) -> quot(z0, z1, z2) quot(z0, 0, s(z1)) -> s(quot(z0, s(z1), s(z1))) Tuples: QUOT(0, s(z0), s(z1)) -> c QUOT(s(z0), s(z1), z2) -> c1(QUOT(z0, z1, z2)) QUOT(z0, 0, s(z1)) -> c2(QUOT(z0, s(z1), s(z1))) S tuples: QUOT(0, s(z0), s(z1)) -> c QUOT(s(z0), s(z1), z2) -> c1(QUOT(z0, z1, z2)) QUOT(z0, 0, s(z1)) -> c2(QUOT(z0, s(z1), s(z1))) K tuples:none Defined Rule Symbols: quot_3 Defined Pair Symbols: QUOT_3 Compound Symbols: c, c1_1, c2_1 ---------------------------------------- (3) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID)) Removed 1 trailing nodes: QUOT(0, s(z0), s(z1)) -> c ---------------------------------------- (4) Obligation: Complexity Dependency Tuples Problem Rules: quot(0, s(z0), s(z1)) -> 0 quot(s(z0), s(z1), z2) -> quot(z0, z1, z2) quot(z0, 0, s(z1)) -> s(quot(z0, s(z1), s(z1))) Tuples: QUOT(s(z0), s(z1), z2) -> c1(QUOT(z0, z1, z2)) QUOT(z0, 0, s(z1)) -> c2(QUOT(z0, s(z1), s(z1))) S tuples: QUOT(s(z0), s(z1), z2) -> c1(QUOT(z0, z1, z2)) QUOT(z0, 0, s(z1)) -> c2(QUOT(z0, s(z1), s(z1))) K tuples:none Defined Rule Symbols: quot_3 Defined Pair Symbols: QUOT_3 popout

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job log

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actions

all output return to Runtime Complexity: TRS Innermost