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TRS Standard pair #516964551
details
property
value
status
complete
benchmark
perfect2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n174.star.cs.uiowa.edu
space
Mixed_TRS
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.0853929519653 seconds
cpu usage
0.046703471
max memory
3411968.0
stage attributes
key
value
output-size
11812
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S u:S x:S y:S z:S) (RULES f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) if(ffalse,x:S,y:S) -> y:S if(ttrue,x:S,y:S) -> x:S le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) minus(0,y:S) -> 0 minus(s(x:S),0) -> s(x:S) minus(s(x:S),s(y:S)) -> minus(x:S,y:S) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) ) Problem 1: Innermost Equivalent Processor: -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) if(ffalse,x:S,y:S) -> y:S if(ttrue,x:S,y:S) -> x:S le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) minus(0,y:S) -> 0 minus(s(x:S),0) -> s(x:S) minus(s(x:S),s(y:S)) -> minus(x:S,y:S) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),0,z:S,u:S) -> MINUS(z:S,s(x:S)) F(s(x:S),s(y:S),z:S,u:S) -> F(s(x:S),minus(y:S,x:S),z:S,u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) F(s(x:S),s(y:S),z:S,u:S) -> IF(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) F(s(x:S),s(y:S),z:S,u:S) -> LE(x:S,y:S) F(s(x:S),s(y:S),z:S,u:S) -> MINUS(y:S,x:S) LE(s(x:S),s(y:S)) -> LE(x:S,y:S) MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) PERFECTP(s(x:S)) -> F(x:S,s(0),s(x:S),s(x:S)) -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) if(ffalse,x:S,y:S) -> y:S if(ttrue,x:S,y:S) -> x:S le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) minus(0,y:S) -> 0 minus(s(x:S),0) -> s(x:S) minus(s(x:S),s(y:S)) -> minus(x:S,y:S) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) Problem 1: SCC Processor: -> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),0,z:S,u:S) -> MINUS(z:S,s(x:S)) F(s(x:S),s(y:S),z:S,u:S) -> F(s(x:S),minus(y:S,x:S),z:S,u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) F(s(x:S),s(y:S),z:S,u:S) -> IF(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) F(s(x:S),s(y:S),z:S,u:S) -> LE(x:S,y:S) F(s(x:S),s(y:S),z:S,u:S) -> MINUS(y:S,x:S) LE(s(x:S),s(y:S)) -> LE(x:S,y:S) MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) PERFECTP(s(x:S)) -> F(x:S,s(0),s(x:S),s(x:S)) -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) if(ffalse,x:S,y:S) -> y:S if(ttrue,x:S,y:S) -> x:S
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