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SRS Standard pair #516969107
details
property
value
status
complete
benchmark
sym-2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n060.star.cs.uiowa.edu
space
Waldmann_06_SRS
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
2.22907209396 seconds
cpu usage
7.28260659
max memory
1.617588224E9
stage attributes
key
value
output-size
64768
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { a ↦ 0, b ↦ 1 }, it remains to prove termination of the 3-rule system { 0 0 0 ⟶ 1 1 1 , 1 0 0 1 ⟶ , 1 0 0 1 ⟶ 1 0 0 0 1 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (0,↓) ↦ 1, (1,↑) ↦ 2, (1,↓) ↦ 3 }, it remains to prove termination of the 8-rule system { 0 1 1 ⟶ 2 3 3 , 0 1 1 ⟶ 2 3 , 0 1 1 ⟶ 2 , 2 1 1 3 ⟶ 2 1 1 1 3 , 2 1 1 3 ⟶ 0 1 1 3 , 1 1 1 →= 3 3 3 , 3 1 1 3 →= , 3 1 1 3 →= 3 1 1 1 3 } Applying sparse tiling TROC(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { (4,0) ↦ 0, (0,1) ↦ 1, (1,1) ↦ 2, (4,2) ↦ 3, (2,3) ↦ 4, (3,3) ↦ 5, (3,1) ↦ 6, (1,3) ↦ 7, (1,5) ↦ 8, (3,5) ↦ 9, (2,1) ↦ 10, (2,5) ↦ 11, (0,3) ↦ 12, (4,1) ↦ 13, (4,3) ↦ 14, (0,5) ↦ 15, (4,5) ↦ 16 }, it remains to prove termination of the 60-rule system { 0 1 2 2 ⟶ 3 4 5 6 , 0 1 2 7 ⟶ 3 4 5 5 , 0 1 2 8 ⟶ 3 4 5 9 , 0 1 2 2 ⟶ 3 4 6 , 0 1 2 7 ⟶ 3 4 5 , 0 1 2 8 ⟶ 3 4 9 , 0 1 2 2 ⟶ 3 10 , 0 1 2 7 ⟶ 3 4 , 0 1 2 8 ⟶ 3 11 , 3 10 2 7 6 ⟶ 3 10 2 2 7 6 , 3 10 2 7 5 ⟶ 3 10 2 2 7 5 , 3 10 2 7 9 ⟶ 3 10 2 2 7 9 , 3 10 2 7 6 ⟶ 0 1 2 7 6 , 3 10 2 7 5 ⟶ 0 1 2 7 5 , 3 10 2 7 9 ⟶ 0 1 2 7 9 , 1 2 2 2 →= 12 5 5 6 , 1 2 2 7 →= 12 5 5 5 , 1 2 2 8 →= 12 5 5 9 , 2 2 2 2 →= 7 5 5 6 , 2 2 2 7 →= 7 5 5 5 , 2 2 2 8 →= 7 5 5 9 , 10 2 2 2 →= 4 5 5 6 , 10 2 2 7 →= 4 5 5 5 , 10 2 2 8 →= 4 5 5 9 , 6 2 2 2 →= 5 5 5 6 , 6 2 2 7 →= 5 5 5 5 , 6 2 2 8 →= 5 5 5 9 , 13 2 2 2 →= 14 5 5 6 , 13 2 2 7 →= 14 5 5 5 , 13 2 2 8 →= 14 5 5 9 , 12 6 2 7 6 →= 1 , 12 6 2 7 5 →= 12 , 12 6 2 7 9 →= 15 , 7 6 2 7 6 →= 2 , 7 6 2 7 5 →= 7 , 7 6 2 7 9 →= 8 , 4 6 2 7 6 →= 10 , 4 6 2 7 5 →= 4 , 4 6 2 7 9 →= 11 , 5 6 2 7 6 →= 6 , 5 6 2 7 5 →= 5 , 5 6 2 7 9 →= 9 , 14 6 2 7 6 →= 13 , 14 6 2 7 5 →= 14 , 14 6 2 7 9 →= 16 , 12 6 2 7 6 →= 12 6 2 2 7 6 , 12 6 2 7 5 →= 12 6 2 2 7 5 , 12 6 2 7 9 →= 12 6 2 2 7 9 , 7 6 2 7 6 →= 7 6 2 2 7 6 , 7 6 2 7 5 →= 7 6 2 2 7 5 , 7 6 2 7 9 →= 7 6 2 2 7 9 , 4 6 2 7 6 →= 4 6 2 2 7 6 , 4 6 2 7 5 →= 4 6 2 2 7 5 , 4 6 2 7 9 →= 4 6 2 2 7 9 , 5 6 2 7 6 →= 5 6 2 2 7 6 , 5 6 2 7 5 →= 5 6 2 2 7 5 , 5 6 2 7 9 →= 5 6 2 2 7 9 , 14 6 2 7 6 →= 14 6 2 2 7 6 , 14 6 2 7 5 →= 14 6 2 2 7 5 , 14 6 2 7 9 →= 14 6 2 2 7 9 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠
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