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SRS Standard pair #516970559
details
property
value
status
complete
benchmark
140639.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
2.95068216324 seconds
cpu usage
10.100999818
max memory
3.644923904E9
stage attributes
key
value
output-size
117143
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 50-rule system { 0 0 0 0 0 0 1 1 1 2 2 2 1 ⟶ 0 1 1 0 0 1 1 1 0 1 1 1 1 1 1 2 1 , 0 0 0 1 1 1 2 0 2 0 1 1 1 ⟶ 1 1 1 1 2 1 1 0 1 1 1 0 1 1 1 0 1 , 0 0 1 0 0 1 2 2 1 0 1 0 1 ⟶ 0 0 1 1 1 0 0 0 1 0 0 1 1 2 1 1 1 , 0 0 1 0 1 0 1 1 2 0 1 2 1 ⟶ 0 0 0 0 1 1 1 2 1 0 0 0 0 0 1 0 1 , 0 0 1 1 1 1 0 0 0 0 2 2 2 ⟶ 0 1 0 0 1 1 1 0 0 1 1 0 2 0 0 1 1 , 0 0 1 1 2 2 0 0 0 1 2 1 2 ⟶ 0 0 0 1 1 0 1 0 0 0 1 2 1 0 2 1 2 , 0 0 1 2 1 1 1 1 0 2 0 1 2 ⟶ 1 0 0 1 1 1 2 0 0 0 1 1 2 0 0 1 2 , 0 0 1 2 2 2 0 1 0 0 0 0 1 ⟶ 0 1 0 1 1 1 2 0 1 0 1 1 0 0 1 1 1 , 0 0 2 1 0 0 1 0 1 0 1 0 0 ⟶ 0 0 0 0 1 0 1 0 1 0 1 0 0 1 1 1 1 , 0 1 0 0 1 0 0 2 0 1 0 1 2 ⟶ 0 0 0 0 1 0 0 0 0 0 1 0 0 2 1 1 1 , 0 1 0 1 0 2 0 1 1 0 1 0 2 ⟶ 0 1 2 0 1 0 0 0 1 0 0 0 1 0 1 0 2 , 0 1 0 2 2 0 0 1 0 1 0 0 1 ⟶ 0 1 1 1 1 2 0 1 1 0 1 0 1 0 1 0 1 , 0 1 1 0 1 0 2 1 1 0 0 2 1 ⟶ 1 1 2 0 0 0 0 0 1 0 1 1 2 2 0 0 1 , 0 1 1 0 1 1 1 1 0 2 0 1 0 ⟶ 0 1 0 0 0 0 0 0 1 0 1 1 2 0 0 0 1 , 0 1 1 1 2 1 0 0 1 1 2 2 1 ⟶ 1 1 0 1 1 2 0 1 1 1 1 0 1 1 2 0 1 , 0 1 2 0 1 1 2 0 0 1 0 1 0 ⟶ 0 1 2 0 0 0 0 0 0 1 2 1 0 0 1 0 0 , 0 1 2 0 2 1 1 2 2 2 1 0 1 ⟶ 0 1 2 0 0 2 1 1 1 2 0 1 1 2 0 1 1 , 0 1 2 2 0 0 2 0 0 1 0 0 0 ⟶ 1 1 2 0 0 1 0 1 2 0 1 0 1 0 0 0 0 , 0 2 1 0 0 0 1 1 2 1 0 1 1 ⟶ 1 1 1 1 0 0 1 1 0 1 2 1 0 1 0 0 1 , 0 2 1 0 1 0 1 0 0 0 2 0 1 ⟶ 0 0 0 0 0 1 0 0 1 1 2 0 1 1 0 0 1 , 0 2 2 0 0 0 0 1 1 1 0 1 1 ⟶ 1 1 1 1 1 1 0 1 0 0 1 1 1 0 1 1 1 , 1 0 0 0 0 0 1 0 2 0 1 2 0 ⟶ 1 0 1 1 1 0 1 1 1 0 0 1 2 2 0 0 0 , 1 0 0 1 0 1 2 0 1 0 1 2 0 ⟶ 0 0 0 1 1 0 1 0 1 2 0 1 0 1 0 1 0 , 1 0 0 1 1 0 0 2 2 0 1 0 1 ⟶ 0 0 0 1 1 1 1 1 0 0 0 0 0 2 1 1 1 , 1 0 1 0 1 0 1 1 1 0 1 2 2 ⟶ 0 1 0 1 1 1 0 0 1 1 0 1 0 0 1 2 1 , 1 0 1 1 2 0 1 2 2 0 0 0 0 ⟶ 1 0 0 0 0 1 0 1 1 2 2 2 0 0 0 0 0 , 1 0 1 2 2 0 1 1 0 2 0 1 1 ⟶ 0 0 1 0 0 1 1 1 0 2 2 2 0 0 0 1 1 , 1 1 0 0 0 0 1 1 1 0 0 2 1 ⟶ 0 1 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 , 1 1 0 0 1 0 1 1 1 0 1 0 2 ⟶ 0 1 1 1 1 1 0 1 0 0 0 1 1 1 1 1 2 , 1 1 0 1 0 0 1 2 1 0 2 1 1 ⟶ 0 1 0 1 0 0 1 0 1 0 2 2 0 1 0 0 1 , 1 1 0 1 1 0 2 0 0 1 0 1 0 ⟶ 0 1 1 0 1 1 0 1 0 0 0 1 1 1 0 0 0 , 1 1 1 1 2 0 1 1 2 0 0 0 0 ⟶ 1 1 0 1 1 0 0 1 1 0 1 1 0 1 0 0 1 , 1 1 1 2 0 0 0 0 1 1 2 1 1 ⟶ 1 1 1 1 1 0 0 0 1 1 0 2 1 0 0 0 1 , 1 1 2 1 0 1 1 1 2 1 0 0 1 ⟶ 0 1 2 2 0 0 0 1 1 0 0 0 0 0 0 1 1 , 1 2 0 0 1 0 1 1 1 0 1 0 0 ⟶ 0 1 0 1 1 0 0 1 1 0 0 0 0 0 0 0 1 , 1 2 0 0 1 1 0 1 1 0 0 0 2 ⟶ 0 0 1 1 0 0 1 1 1 1 0 1 1 0 1 1 1 , 1 2 1 0 1 1 1 0 1 1 0 0 2 ⟶ 0 0 1 0 0 0 1 1 0 0 0 2 0 0 0 1 2 , 1 2 1 2 2 0 1 1 1 0 1 0 0 ⟶ 0 1 2 1 0 1 0 0 2 1 1 0 0 1 1 0 0 , 1 2 2 2 1 1 0 1 1 0 2 0 0 ⟶ 1 0 0 0 0 0 1 2 2 1 2 1 0 0 2 0 0 , 1 2 2 2 1 2 0 0 0 1 2 1 0 ⟶ 1 1 1 0 0 2 1 1 0 2 0 1 1 2 0 1 0 , 2 0 0 0 0 1 2 1 2 0 1 2 0 ⟶ 2 0 0 1 1 0 1 0 0 2 1 0 1 1 2 0 0 , 2 0 0 1 1 2 0 1 0 1 1 0 1 ⟶ 0 1 0 0 0 2 0 0 0 1 0 1 0 1 1 0 1 , 2 0 1 0 0 1 0 0 1 2 1 0 0 ⟶ 1 1 1 0 0 0 1 0 0 1 0 0 0 1 0 1 0 , 2 0 1 0 0 2 1 1 0 2 1 2 2 ⟶ 2 1 1 0 0 1 1 0 1 1 1 0 2 1 2 2 2 , 2 0 1 0 2 0 1 1 1 1 0 0 1 ⟶ 0 2 1 1 1 0 1 0 1 0 1 1 1 1 1 0 1 , 2 0 1 1 0 0 0 1 0 0 2 2 1 ⟶ 2 0 0 0 1 1 2 1 0 0 0 0 1 2 0 0 1 , 2 0 1 1 0 0 1 1 1 1 2 0 0 ⟶ 2 0 0 1 1 0 0 0 0 1 0 1 0 0 0 0 0 , 2 1 2 2 0 0 0 1 0 1 0 1 0 ⟶ 2 1 1 1 0 1 0 0 0 0 0 1 2 1 1 1 0 , 2 2 0 0 0 1 1 0 1 1 1 0 0 ⟶ 1 0 1 1 0 0 1 1 0 0 0 0 0 0 1 1 1 , 2 2 0 1 1 0 0 1 0 1 1 1 1 ⟶ 2 1 0 0 0 0 0 1 1 1 0 1 0 1 1 0 1 } Applying sparse tiling TRFC(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { (0,0) ↦ 0, (0,1) ↦ 1, (1,1) ↦ 2, (1,2) ↦ 3, (2,2) ↦ 4, (2,1) ↦ 5, (1,0) ↦ 6, (1,4) ↦ 7, (2,0) ↦ 8, (3,0) ↦ 9, (0,2) ↦ 10, (3,1) ↦ 11, (2,4) ↦ 12, (0,4) ↦ 13, (3,2) ↦ 14 }, it remains to prove termination of the 800-rule system { 0 0 0 0 0 0 1 2 2 3 4 4 5 6 ⟶ 0 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 6 , 0 0 0 0 0 0 1 2 2 3 4 4 5 2 ⟶ 0 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 2 , 0 0 0 0 0 0 1 2 2 3 4 4 5 3 ⟶ 0 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 3 , 0 0 0 0 0 0 1 2 2 3 4 4 5 7 ⟶ 0 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 7 , 6 0 0 0 0 0 1 2 2 3 4 4 5 6 ⟶ 6 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 6 , 6 0 0 0 0 0 1 2 2 3 4 4 5 2 ⟶ 6 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 2 , 6 0 0 0 0 0 1 2 2 3 4 4 5 3 ⟶ 6 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 3 , 6 0 0 0 0 0 1 2 2 3 4 4 5 7 ⟶ 6 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 7 , 8 0 0 0 0 0 1 2 2 3 4 4 5 6 ⟶ 8 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 6 , 8 0 0 0 0 0 1 2 2 3 4 4 5 2 ⟶ 8 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 2 , 8 0 0 0 0 0 1 2 2 3 4 4 5 3 ⟶ 8 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 3 , 8 0 0 0 0 0 1 2 2 3 4 4 5 7 ⟶ 8 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 7 , 9 0 0 0 0 0 1 2 2 3 4 4 5 6 ⟶ 9 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 6 , 9 0 0 0 0 0 1 2 2 3 4 4 5 2 ⟶ 9 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 2 , 9 0 0 0 0 0 1 2 2 3 4 4 5 3 ⟶ 9 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 3 , 9 0 0 0 0 0 1 2 2 3 4 4 5 7 ⟶ 9 1 2 6 0 1 2 2 6 1 2 2 2 2 2 3 5 7 , 0 0 0 1 2 2 3 8 10 8 1 2 2 6 ⟶ 1 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 6 , 0 0 0 1 2 2 3 8 10 8 1 2 2 2 ⟶ 1 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 2 , 0 0 0 1 2 2 3 8 10 8 1 2 2 3 ⟶ 1 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 3 , 0 0 0 1 2 2 3 8 10 8 1 2 2 7 ⟶ 1 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 7 , 6 0 0 1 2 2 3 8 10 8 1 2 2 6 ⟶ 2 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 6 , 6 0 0 1 2 2 3 8 10 8 1 2 2 2 ⟶ 2 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 2 , 6 0 0 1 2 2 3 8 10 8 1 2 2 3 ⟶ 2 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 3 , 6 0 0 1 2 2 3 8 10 8 1 2 2 7 ⟶ 2 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 7 , 8 0 0 1 2 2 3 8 10 8 1 2 2 6 ⟶ 5 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 6 , 8 0 0 1 2 2 3 8 10 8 1 2 2 2 ⟶ 5 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 2 , 8 0 0 1 2 2 3 8 10 8 1 2 2 3 ⟶ 5 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 3 , 8 0 0 1 2 2 3 8 10 8 1 2 2 7 ⟶ 5 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 7 , 9 0 0 1 2 2 3 8 10 8 1 2 2 6 ⟶ 11 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 6 , 9 0 0 1 2 2 3 8 10 8 1 2 2 2 ⟶ 11 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 2 , 9 0 0 1 2 2 3 8 10 8 1 2 2 3 ⟶ 11 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 3 , 9 0 0 1 2 2 3 8 10 8 1 2 2 7 ⟶ 11 2 2 2 3 5 2 6 1 2 2 6 1 2 2 6 1 7 , 0 0 1 6 0 1 3 4 5 6 1 6 1 6 ⟶ 0 0 1 2 2 6 0 0 1 6 0 1 2 3 5 2 2 6 , 0 0 1 6 0 1 3 4 5 6 1 6 1 2 ⟶ 0 0 1 2 2 6 0 0 1 6 0 1 2 3 5 2 2 2 , 0 0 1 6 0 1 3 4 5 6 1 6 1 3 ⟶ 0 0 1 2 2 6 0 0 1 6 0 1 2 3 5 2 2 3 ,
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