SRS Standard pair #516973271

details

property	value
status	complete
benchmark	x02.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n089.star.cs.uiowa.edu
space	Secret_07_SRS

run statistics

property	value
solver	MnM 3.18b
configuration	default
runtime (wallclock)	1.59747505188 seconds
cpu usage	4.637632871
max memory	7.5698176E8

stage attributes

key	value
output-size	16243
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2, d ↦ 3, e ↦ 4 },
it remains to prove termination of the 6-rule system
{ 0 1 ⟶ 2 3 ,
  3 3 ⟶ 1 4 ,
  1 ⟶ 3 2 ,
  3 ⟶ ,
  4 2 ⟶ 3 0 ,
  0 ⟶ 4 3 }

Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols.

After renaming modulo the bijection { (0,↑) ↦ 0, (1,↓) ↦ 1, (3,↑) ↦ 2, (3,↓) ↦ 3, (1,↑) ↦ 4, (4,↓) ↦ 5, (4,↑) ↦ 6, (2,↓) ↦ 7, (0,↓) ↦ 8 },
it remains to prove termination of the 14-rule system
{ 0 1 ⟶ 2 ,
  2 3 ⟶ 4 5 ,
  2 3 ⟶ 6 ,
  4 ⟶ 2 7 ,
  6 7 ⟶ 2 8 ,
  6 7 ⟶ 0 ,
  0 ⟶ 6 3 ,
  0 ⟶ 2 ,
  8 1 →= 7 3 ,
  3 3 →= 1 5 ,
  1 →= 3 7 ,
  3 →= ,
  5 7 →= 3 8 ,
  8 →= 5 3 }

Applying sparse tiling TROC(2) [Geser/Hofbauer/Waldmann, FSCD 2019].

After renaming modulo the bijection { (9,0) ↦ 0, (0,1) ↦ 1, (1,1) ↦ 2, (9,2) ↦ 3, (2,1) ↦ 4, (1,3) ↦ 5, (2,3) ↦ 6, (1,5) ↦ 7, (2,5) ↦ 8, (1,7) ↦ 9, (2,7) ↦ 10, (1,8) ↦ 11, (2,8) ↦ 12, (1,10) ↦ 13, (2,10) ↦ 14, (3,1) ↦ 15, (9,4) ↦ 16, (4,5) ↦ 17, (5,1) ↦ 18, (3,3) ↦ 19, (5,3) ↦ 20, (3,5) ↦ 21, (5,5) ↦ 22, (3,7) ↦ 23, (5,7) ↦ 24, (3,8) ↦ 25, (5,8) ↦ 26, (3,10) ↦ 27, (5,10) ↦ 28, (9,6) ↦ 29, (6,1) ↦ 30, (6,3) ↦ 31, (6,5) ↦ 32, (6,7) ↦ 33, (6,8) ↦ 34, (6,10) ↦ 35, (4,1) ↦ 36, (7,1) ↦ 37, (4,3) ↦ 38, (7,3) ↦ 39, (7,5) ↦ 40, (4,7) ↦ 41, (7,7) ↦ 42, (4,8) ↦ 43, (7,8) ↦ 44, (4,10) ↦ 45, (7,10) ↦ 46, (8,1) ↦ 47, (8,3) ↦ 48, (8,5) ↦ 49, (8,7) ↦ 50, (8,8) ↦ 51, (8,10) ↦ 52, (0,3) ↦ 53, (0,5) ↦ 54, (0,7) ↦ 55, (0,8) ↦ 56, (0,10) ↦ 57, (9,8) ↦ 58, (9,7) ↦ 59, (9,3) ↦ 60, (9,1) ↦ 61, (9,5) ↦ 62, (9,10) ↦ 63 },
it remains to prove termination of the 408-rule system
{ 0 1 2 ⟶ 3 4 ,
  0 1 5 ⟶ 3 6 ,
  0 1 7 ⟶ 3 8 ,
  0 1 9 ⟶ 3 10 ,
  0 1 11 ⟶ 3 12 ,
  0 1 13 ⟶ 3 14 ,
  3 6 15 ⟶ 16 17 18 ,
  3 6 19 ⟶ 16 17 20 ,
  3 6 21 ⟶ 16 17 22 ,
  3 6 23 ⟶ 16 17 24 ,
  3 6 25 ⟶ 16 17 26 ,
  3 6 27 ⟶ 16 17 28 ,
  3 6 15 ⟶ 29 30 ,
  3 6 19 ⟶ 29 31 ,
  3 6 21 ⟶ 29 32 ,
  3 6 23 ⟶ 29 33 ,
  3 6 25 ⟶ 29 34 ,
  3 6 27 ⟶ 29 35 ,
  16 36 ⟶ 3 10 37 ,
  16 38 ⟶ 3 10 39 ,
  16 17 ⟶ 3 10 40 ,
  16 41 ⟶ 3 10 42 ,
  16 43 ⟶ 3 10 44 ,
  16 45 ⟶ 3 10 46 ,
  29 33 37 ⟶ 3 12 47 ,
  29 33 39 ⟶ 3 12 48 ,
  29 33 40 ⟶ 3 12 49 ,
  29 33 42 ⟶ 3 12 50 ,
  29 33 44 ⟶ 3 12 51 ,
  29 33 46 ⟶ 3 12 52 ,
  29 33 37 ⟶ 0 1 ,
  29 33 39 ⟶ 0 53 ,
  29 33 40 ⟶ 0 54 ,
  29 33 42 ⟶ 0 55 ,
  29 33 44 ⟶ 0 56 ,
  29 33 46 ⟶ 0 57 ,
  0 1 ⟶ 29 31 15 ,
  0 53 ⟶ 29 31 19 ,
  0 54 ⟶ 29 31 21 ,
  0 55 ⟶ 29 31 23 ,
  0 56 ⟶ 29 31 25 ,
  0 57 ⟶ 29 31 27 ,
  0 1 ⟶ 3 4 ,
  0 53 ⟶ 3 6 ,
  0 54 ⟶ 3 8 ,
  0 55 ⟶ 3 10 ,
  0 56 ⟶ 3 12 ,
  0 57 ⟶ 3 14 ,
  56 47 2 →= 55 39 15 ,
  56 47 5 →= 55 39 19 ,
  56 47 7 →= 55 39 21 ,
  56 47 9 →= 55 39 23 ,
  56 47 11 →= 55 39 25 ,
  56 47 13 →= 55 39 27 ,
  11 47 2 →= 9 39 15 ,
  11 47 5 →= 9 39 19 ,
  11 47 7 →= 9 39 21 ,
  11 47 9 →= 9 39 23 ,
  11 47 11 →= 9 39 25 ,
  11 47 13 →= 9 39 27 ,

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