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SRS Standard pair #516975353
details
property
value
status
complete
benchmark
size-12-alpha-3-num-287.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n088.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.36476278305 seconds
cpu usage
3.8025176
max memory
8.37033984E8
stage attributes
key
value
output-size
6109
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 4-rule system { 0 ⟶ , 0 1 ⟶ 2 1 2 1 , 1 ⟶ 0 0 , 2 2 ⟶ } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (1,↓) ↦ 1, (2,↑) ↦ 2, (2,↓) ↦ 3, (1,↑) ↦ 4, (0,↓) ↦ 5 }, it remains to prove termination of the 9-rule system { 0 1 ⟶ 2 1 3 1 , 0 1 ⟶ 4 3 1 , 0 1 ⟶ 2 1 , 4 ⟶ 0 5 , 4 ⟶ 0 , 5 →= , 5 1 →= 3 1 3 1 , 1 →= 5 5 , 3 3 →= } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 4 ↦ 2, 3 ↦ 3, 5 ↦ 4 }, it remains to prove termination of the 7-rule system { 0 1 ⟶ 2 3 1 , 2 ⟶ 0 4 , 2 ⟶ 0 , 4 →= , 4 1 →= 3 1 3 1 , 1 →= 4 4 , 3 3 →= } Applying sparse tiling TROC(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { (5,0) ↦ 0, (0,1) ↦ 1, (1,1) ↦ 2, (5,2) ↦ 3, (2,3) ↦ 4, (3,1) ↦ 5, (1,3) ↦ 6, (1,4) ↦ 7, (1,6) ↦ 8, (2,1) ↦ 9, (0,4) ↦ 10, (4,1) ↦ 11, (4,3) ↦ 12, (2,4) ↦ 13, (4,4) ↦ 14, (2,6) ↦ 15, (4,6) ↦ 16, (0,3) ↦ 17, (0,6) ↦ 18, (3,4) ↦ 19, (3,3) ↦ 20, (3,6) ↦ 21, (5,4) ↦ 22, (5,1) ↦ 23, (5,3) ↦ 24, (5,6) ↦ 25 }, it remains to prove termination of the 108-rule system { 0 1 2 ⟶ 3 4 5 2 , 0 1 6 ⟶ 3 4 5 6 , 0 1 7 ⟶ 3 4 5 7 , 0 1 8 ⟶ 3 4 5 8 , 3 9 ⟶ 0 10 11 , 3 4 ⟶ 0 10 12 , 3 13 ⟶ 0 10 14 , 3 15 ⟶ 0 10 16 , 3 9 ⟶ 0 1 , 3 4 ⟶ 0 17 , 3 13 ⟶ 0 10 , 3 15 ⟶ 0 18 , 10 11 →= 1 , 10 12 →= 17 , 10 14 →= 10 , 10 16 →= 18 , 7 11 →= 2 , 7 12 →= 6 , 7 14 →= 7 , 7 16 →= 8 , 13 11 →= 9 , 13 12 →= 4 , 13 14 →= 13 , 13 16 →= 15 ,
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